[英]rmongodb: substract date in aggregation
After finally figuring out how to parameterize an aggregation pipeline with a date using mongo.bson.from.list()
, I've been wrangling with the snippet below to get the $min
for the date difference below, but keep getting 在最终弄清楚如何使用
mongo.bson.from.list()
参数化带有日期的聚合管道之后,我一直在与下面的代码段进行mongo.bson.from.list()
,以获取下面的日期差的$min
,但是请继续获取
Error in mongo.aggregation(m, collection , aggregation_pipeline ) :
mongoDB error: 10. Please check ?mongo.get.err for more details.
which means that my BSON group expression, although acceptable to mongo.bson.from.list()
, is rejected by mongo.aggregation()
. 这意味着,我的BSON组表达,尽管接受
mongo.bson.from.list()
是由拒绝mongo.aggregation()
I've tried using list()
rather than c()
, and cod
rather than its ISODate definition, with various quoting variations. 我尝试使用
list()
而不是c()
,并使用cod
而不是其ISODate定义,并带有各种引号。
cod <- as.POSIXct("2015-01-01 00:00:00" , tz = "GMT" )
grouparg_bson1 <- mongo.bson.from.list(
list( '$group' = list( '_id' = list('ID' = '$dcmt.cid') ,
'dtdiff' = list('$min' = list('$subtract' = c('$dcmt.orddt','ISODate("2015-01-01T00:00:00Z")' )) ),
'tota' = list('$sum' = '$dcmt.A' ),
'list' = list('$addToSet' = '$dcmt.B' )
))
)
I am using mongo's latest stable release, version 3.2.4. 我正在使用mongo的最新稳定版本3.2.4。
Trial & error: the following works. 试错:以下工作。
grouparg_bson1 <- mongo.bson.from.list(
list( '$group' = list( '_id' = list('ID' = '$dcmt.cid') ,
'dtdiff' = list('$min' = list('$subtract' = list('$dcmt.orddt', cod )) ),
'tota' = list('$sum' = '$dcmt.A' ),
'list' = list('$addToSet' = '$dcmt.B' )
))
)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.