MYSQL - 获取 A 列小于 B 列的行

Question

Table (showing only relevant columns)

ID | product_name | stock | stock_level
6  | test name    | 5     | 4
 7 | test name 2  | 3     | 9

I have a lot more rows in my database.

In MYSQL, how can I get every row where the stock value is less than the stock_level value?

Answer 1

Like this?

SELECT * FROM table WHERE stock < stock_level

That would return row2 (stock = 3, stock_level= 9) but not row1 (stock = 5, stock_level= 4).

<?php
$result = mysqli_query($myslqi, "SELECT * FROM table WHERE stock < stock_level")) {
  ....
}