将shell脚本变量作为参数传递给Python脚本

Question

Am writing shell script which takes argument,

while getopts ":i:o:m" opt; do
  case $opt in
    i) a="$OPTARG"
    ;;
    o) b="$OPTARG"
    ;;
    m) c="$OPTARG"
    ;;
    \?) echo "Invalid option -$OPTARG" >&3
    ;;
  esac
done  

then am adding

python filename.py a b c

instead value of variable, variable name is sent to the Python program.

Please help to solve this problem.

Answer 1

When you want to get the value of variable in shell use $variable_name. See the below example

root@s:/tmp# cat t.sh
#!/bin/sh
a="test"
b="test2"
c="test3"
python test.py $a $b $c

root@s:/tmp# cat test.py
#!/usr/bin/python
import sys
print  sys.argv[1:]


root@s:/tmp# ./t.sh
['test', 'test2', 'test3']

Answer 2

You can access environment variables by name, but you need to export them.

on bash

myvariable="something"
export myvariable

on python

import os
print os.environ["myvariable"]