[英]split a multi-line string in C
how can I split a multi-line string in const char* array.? 如何在const char *数组中拆分多行字符串?
Here is the input string. 这是输入字符串。
const char* str = "122.123,-38.789"
"122.123,-39.78";
I need to get two string from this. 我需要从中得到两个字符串。
str1 = "122.123,-38.789";
str2 = "122.123,-39.78";
output of 输出
printf("string='%s'", str)
string='122.123,-38.789122.123,-39.78'
What should be done to split this string ? 应该怎么做才能拆分此字符串?
Use an array of char * 使用char数组*
#include <stdio.h>
const char* str[] = { "122.123,-38.789" , "122.123,-39.78" };
int main(){
printf("%s\n%s\n",str[0],str[1] );
return 0;
}
The C pre-processor concats strings placed together, C预处理器将字符串放置在一起,
const char* str = "122.123,-38.789"
"122.123,-39.78";
The linebreak between the strings is parsed as a blank, treated the same as a space or a tab. 字符串之间的换行符被解析为空白,与空格或制表符相同。 So it's equivalent to: 因此,它等效于:
const char* str = "122.123,-38.789" "122.123,-39.78";
which the preprocessor converts to 预处理器转换为
const char* str = "122.123,-38.789122.123,-39.78";
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