运行.bashrc时找不到别名命令

Question

I'm trying to do the simplest of shell aliases like I always use to do.

Here's my .bashrc (and same happened with ZSH and .zshrc) for instance :

alias ll=“ls -al”
alias edit_http=“open -e /etc/httpd/conf/httpd.conf”

and here's my $PATH variable :

/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin

When I open a new terminal window I get this :

-bash: alias: -al”: not found
-bash: alias: -e: not found
-bash: alias: /etc/httpd/conf/httpd.conf”: not found

Here's my ls -al result of .bashrc :

-rwxr-xr-x@   1 ed    staff     78 Mar 17 03:55 .bashrc

Strangely I can type this into Terminal and it works :

alias ll="ls -al"

But not from within the .bashrc file.

Any suggestions ? I've checked so many forum entries and nothing worked so far.

Answer 1

It looks like something went wrong during copying the alias into your .bashrc.

You ended up with 'wrong' quotation mark. Replace “ with " and it should work. “ is unicode but you require ascii quotation marks. For testing you can use this .bashrc

# bashrc example
# won't work
alias ll=“ls -al”
# will work
alias la="ls -al"

And with this code you can verify your problem:

$ source .bashrc
-bash: alias: -al”: not found
$ ll
-bash: “ls: command not found
$ la
total 0
drwxr-xr-x   2 alneuman  staff    68 Mar 17 12:18 .
drwxrwxrwx+ 70 alneuman  staff  2380 Mar 17 12:18 ..

Have a look here at unix.stackexchange. Somebody had the same issue. Brave new unicode world ;)