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在javascript中将对象从星期日到星期六排序

[英]sorting object Sunday to Saturday in javascript

Hello Everyone i know this question is asked several time but i am not getting exact answer to my question. 大家好我知道这个问题有几次被问到,但我没有得到我的问题的确切答案。

 // I have array of object like this data=[ // "sunday": 1, // << sunday is first day of week {DayOfWeek:"Saturday", TotalCount:30}, {DayOfWeek:"Friday", TotalCount:10}, {DayOfWeek:"Monday", TotalCount:23}, {DayOfWeek:"Sunday", TotalCount:18}, {DayOfWeek:"Wednesday", TotalCount:20} ]; // I need sorted like this: data=[ // "sunday": 1, // << sunday is first day of week {DayOfWeek:"Sunday", TotalCount:18}, {DayOfWeek:"Monday", TotalCount:23}, {DayOfWeek:"Wednesday", TotalCount:20}, {DayOfWeek:"Friday", TotalCount:10}, {DayOfWeek:"Saturday", TotalCount:30} ]; 

I tried this one but I am not able to get the expected result. 我试过这个,但我无法得到预期的结果。 it is giving me a sorted array by starting alphabet like 它通过启动字母表给我一个排序的数组

Friday, Saturday. 星期五星期六。

var sorter = { // "sunday": 1, // << sunday is first day of week "sunday": 1, "monday": 2, "tuesday": 3, "wednesday": 4, "thursday": 5, "friday": 6, "saturday": 7 } var sorter = {//“sunday”:1,//“星期日是星期几的第一天”星期日“:1,”星期一“:2,”星期二“:3,”星期三“:4,”星期四“: 5,“星期五”:6,“星期六”:7}

  var result= data.sort(function sortByDay(a, b) {
    var day1 = a.DayOfWeek.toLowerCase();
    var day2 = b.DayOfWeek.toLowerCase();
    return sorter[day1] > sorter[day2];
  });

Please help me, Thanks in advance. 请帮帮我,提前致谢。

You can sort it with an object for the order, as you already had, but you need the difference 您可以使用订单的对象对其进行排序,就像您已经拥有的那样,但是您需要区别

return order[a.DayOfWeek] - order[b.DayOfWeek];

as a return value for the sort callback. 作为排序回调的返回值。

 var data = [{ DayOfWeek: "Saturday", TotalCount: 30 }, { DayOfWeek: "Friday", TotalCount: 10 }, { DayOfWeek: "Monday", TotalCount: 23 }, { DayOfWeek: "Sunday", TotalCount: 18 }, { DayOfWeek: "Wednesday", TotalCount: 20 }], order = { Sunday: 1, Monday: 2, Tuesday: 3, Wednesday: 4, Thursday: 5, Friday: 6, Saturday: 7 }; data.sort(function (a, b) { return order[a.DayOfWeek] - order[b.DayOfWeek]; }); document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>'); 

There aren't any built-in functions, but it shouldn't be too hard to make a solution. 没有任何内置功能,但解决方案不应该太难。 Here's an example: 这是一个例子:

function s(a,b){
    return daysOfWeek.indexOf(a) - daysOfWeek.indexOf(b); // basic sort function that compares the indexes of the two days
}
var inputArray = ["Saturday", "Monday", "Sunday", "Tuesday"]; // input
var daysOfWeek = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]; // array of days sorted
console.log(inputArray.sort(s)); // output

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