[英]php regex extract pattern but only the number inside it
I get data via a web service that I need to parse to find some value (sunshine duration) and this in php. 我通过Web服务获取数据,我需要对其进行解析以找到一些值(光照持续时间),并且该数据在php中。 My idea would be to do it with regex. 我的想法是使用正则表达式。
I can already find the desired pattern sunshine: 7.5 h
, but I only need the 7.2
(as a number actually) out of the found match. 我已经可以找到所需的模式sunshine: 7.5 h
,但是我只需要找到的匹配项中有7.2
(实际上是一个数字)。 What would be the most straight forward way to do this in PHP? 用PHP做到这一点的最直接的方法是什么?
Can I do it in one pre_match
, or will I need to to 2 x pre_match
(second one on the match of the first one)? 我可以在一个pre_match
完成它,还是需要2 x pre_match
(第二个在第一个匹配中)?
My code: 我的代码:
//test data
$testInputs = array (
0 => "blabla sunshine: 7 h blabla",
1 => "blabla sunshine: 7.5 h blabla",
2 => "blabla sunshine: 0.5 h blabla"
);
//pattern
$pattern = '/sunshine: [\d]*.?[\d]*/';
//test
foreach($testInputs as $testInput)
{
preg_match($pattern, $testInput, $matches, PREG_OFFSET_CAPTURE);
print($testInput);
print_r($matches);
print("<br>");
}
output 输出
sunshine: 7 h Array ( [0] => Array ( [0] => sunshine: 7 [1] => 1 ) )
sunshine: 7.5 h Array ( [0] => Array ( [0] => sunshine: 7.5 [1] => 1 ) )
sunshine: 0.5 h Array ( [0] => Array ( [0] => sunshine: 0.5 [1] => 1 ) )
Simply add brackets to captured desired digits: 只需将括号添加到捕获的所需数字即可:
'/sunshine: ([\d]*.?[\d]*)/'
The performs your preg_match
without PREG_OFFSET_CAPTURE
: 无需PREG_OFFSET_CAPTURE
执行您的preg_match
:
preg_match($pattern, $testInput, $matches);
And in your matches[1]
array you will found the desired result. 在您的matches[1]
数组中,您将找到所需的结果。
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