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是否有可能通过javascript中的函数名称获取参数

[英]is it possible to get parameters by function name in javascript

For example, I have a function defined as below: 例如,我有一个定义如下的函数:

var fn1 = function(obj, p1, p2) {}

Is it possible to get this function's parameters by the function name fn1 outside fn1? 是否可以通过fn1之外的函数名称fn1获取此函数的参数?
I want to make a new fn2(p1, p2) dynamically and in this function passing the obj to call fn1 ? 我想动态制作一个新的fn2(p1, p2)并在此函数中将obj传递给fn1
Anyone help on this? 有人帮忙吗? Many thanks. 非常感谢。

You don't need to pass the scope to the function like this: 您不需要像这样将范围传递给function

var fn1 = function(scope, p1, p2) {}

I belive what you want is something like the call method. 我相信您想要的是类似call方法的东西。 The call method is used to call a method on behalf of another object. call方法用于代表另一个对象调用方法。 It allows you to change the this object of a function from the original context to the new object specified by first arg. 它允许您将函数的this对象从原始上下文更改为first arg指定的新对象。 call Method Ref. call方法参考。 - JS -JS

Here some example: 这里有一些例子:

var fn1 = function(p1,p2){};

var fnThatCall = function(p1,p2){
   var scpe = this;
   fn1.call(scope,p1,p2);
};

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