source 命令没有使用 shell 脚本将变量导出到 zsh 环境

Question

I have a really simple shell script which work really well on bash and export the varialbes to the current bash enviornment but unfortunately it didn't export the variables to the zsh enviornment.

#!/bin/bash
export AWS_ACCESS_KEY_ID=$(echo $RESULT | jq --raw-output .Credentials.AccessKeyId)
export AWS_SECRET_ACCESS_KEY=$(echo $RESULT | jq --raw-output .Credentials.SecretAccessKey)
export AWS_SECURITY_TOKEN=$(echo $RESULT | jq --raw-output .Credentials.SessionToken)

and I am running this script like this:

source myscript.sh

OR

. ./myscript.sh

Please advise, that how I can make it work on the zsh environment?

Answer 1

There is nothing wrong in the code you have posted.

Are your variables simply not defined, or are they defined and not exported, in the sourcing script?

I would turn on set -x before sourcing, and analyze the output. Maybe you have some commands in your sourced script, where the behaviour differs between bash and zsh. From the three lines you have posted, I don't see any incompatibilities though.