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在jquery中将值推送到数组

[英]Push values to array in jquery

I have List of items data and empty array quotations : 我有项目列表data and empty array quotations

   var data = {};
   var quotations = [];

I want to fill quotations with data values ,Every time i add new data it added successfully but all data values get last value . 我想用数据值填充quotations ,每次添加新数据时,它都会成功添加,但所有数据值都会获得最后一个值。

for example : 例如 :

 $("#addquotation").click(function () {
        debugger;
        var itemname = $("#itemname").val();
        var cost =parseFloat( $("#cost").val());
        var notes = $("#notes").val();
        var date = $("#date").val();


        data.Item = itemname;
        data.Cost = cost;
        data.Notes = notes;
        data.Date = date;

        quotations.push(data);
)};

for first time i add 我第一次添加

"test,45,testnotes,2016-02-03" Second time i 've added "test2,45.2,testnotes2,2016-02-05" “test,45,testnotes,2016-02-03”第二次我添加了“test2,45.2,testnotes2,2016-02-05”

when i debug i get data as : 当我调试我获取数据为:

obj(0): "test2,45.2,testnotes2,2016-02-05" obj(1):"test2,45.2,testnotes2,2016-02-05" obj(0):“test2,45.2,testnotes2,2016-02-05”obj(1):“test2,45.2,testnotes2,2016-02-05”

it seems it append last version to all data 它似乎将最后一个版本附加到所有数据

Please Advice . 请指教 。 Thanks 谢谢

You need to declare data inside the click handler, if it's declared as a global variable you are basically always modifying and adding the same data object to the array: 您需要在click处理程序中声明数据,如果它被声明为全局变量,您基本上总是在修改并向数组添加相同的数据对象:

var quotations = [];

$("#addquotation").click(function () {
        debugger;
        var data = {};
        var itemname = $("#itemname").val();
        var cost =parseFloat( $("#cost").val());
        var notes = $("#notes").val();
        var date = $("#date").val();


        data.Item = itemname;
        data.Cost = cost;
        data.Notes = notes;
        data.Date = date;

        quotations.push(data);
)};

You are pushing the same object reference each time since you declared data outside of the click handler. 由于您在单击处理程序之外声明data ,因此每次都推送相同的对象引用。

Change from : 改变自:

var data={};
$("#addquotation").click(function () {

To

$("#addquotation").click(function () {
     var data={};// declare local variable

The problem is that data is a global variable and you add a reference to data to quotations . 问题是data是一个全局变量,您可以将data引用添加到quotations

When the first value is pushed to quotations , data and quotations[0] refer to the same object. 当第一个值被推送到quotationsdataquotations[0]引用同一个对象。 Here is an example of what is happening: 这是一个正在发生的事情的例子:

var a = {num: 1};
var b = a;
b.num = 2;
console.log(a.num); // prints 2

The same thing happens when an object is pushed to an array. 将对象推送到数组时会发生同样的事情。 quotations does not contain a copy of data , it contains a reference to data so that modifying data also modifies quotations . quotations不包含data副本,它包含对data的引用,以便修改data也可以修改quotations To fix this, each element of quotations must refer to a different data object. 要解决此问题, quotations每个元素都必须引用不同的数据对象。 This can be accomplished by defining data inside of the function instead of outside. 这可以通过在函数内部而不是在外部定义data来实现。

Replace 更换

var data = {};
$("#addquotation").click(function() {
    // populate data, push to quotations
});

with

$("#addquotation").click(function() {
    var data = {};
    // populate data, push to quotations
});

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