如何使用random.shuffle获取列表形状的字典值

Question

I seemed to have hit a small snag. I have a program that gets a dictionary with couple of keys and values:

dict = {"M" : ["L", "V", "A"], "C": ["N", "K", "W"]}

Now, I am trying to make a function that will, being provided a dictionary and a key from it, return that particular key's value, so:

def value(dictionary, key)
   return dictionary[key]

that I managed to succeed, but the problem arises when I try to return that particular list in a random order, working with random.shuffle() . It however keeps returning None . Anyone got any ideas?

Answer 1

as shuffle operates in-place, return the list after shuffle as follows:

from random import shuffle
sample_dict = {"M": ["L", "V", "A"], "C": ["N", "K", "W"]}


def get_value(dictionary, key):
    a = dictionary[key]
    shuffle(a)
    return a

b = get_value(sample_dict, "M")
print b