SQL DateDiff-当一个日期字段比另一日期字段早两个月时返回行

Question

Each row has a BookedMonth and a ReportingMonth. I want to return the rows where the ReportingMonth is 2 Months greater than the BookedMonth.

ReportingMonth      BookedMonth
2016-01-01 00:00:00 2015-11-01 00:00:00
2016-01-01 00:00:00 2015-12-01 00:00:00
2016-01-01 00:00:00 2016-01-01 00:00:00

WHERE

DATEDIFF,BookedMonth,ReportingMonth,2

Answer 1

Something like:

select * from table where datediff(month, ReportingMonth, BookedMonth) > 2;

EDIT

Or better... se comments here below:

select * from table where ReportingMonth > dateadd(month, 2, BookedMonth);