java.math.BigInteger与java.lang.Long不兼容

Question

private List getListByInsuredName(TxnListHelper listHelper) throws DAOException{
        Session session = null;
        session = getHibernateSession();
        String query = "SELECT txnRecNo From TxnInsured WHERE InsuredName LIKE :insuredname";
        Query getList = session.createSQLQuery(query);

        if(!GenericValidator.isBlankOrNull(listHelper.getInsuredName())){
            getList.setParameter("insuredname", "%" + listHelper.getInsuredName() + "%");   
        }

        List txnRecNoList = getList.list();
        return txnRecNoList;
    }

criteria.add(Restrictions.in("txnRecNo", getListByInsuredName(listHelper)));

txnRecNo is of bigint type field in database i want to add in criteria, and it is showing an exception java.lang.ClassCastException: java.math.BigInteger incompatible with java.lang.Long

Answer 1

BigInteger can hold an arbitrary amount of data. It can be way bigger than Long.MAX_VALUE.

To convert the value, use txnRecNo.longValue()

Answer 2

From Java Doc: public int intValue()

Converts this BigInteger to an int. This conversion is analogous to a narrowing primitive conversion from long to int as defined in section 5.1.3 of The Java™ Language Specification: if this BigInteger is too big to fit in an int, only the low-order 32 bits are returned. Note that this conversion can lose information about the overall magnitude of the BigInteger value as well as return a result with the opposite sign.

use intValue() method to convert BigInteger to long:

txnRecNo.longValue()