Php：While循环组输出

Question

I have two columns in my database, year and content i want to group the content by year (i have a lot of content and many years not only 2015 and 2016 as the example )

so i'll have this output in html

 <div class="all"> <div class="2016"> 2016 <div class="content_2016"> All the content of the column that is in the same ligne as 2016 in the database </div> </div> <div class="2015"> 2015 <div class="content_2015"> All the content of the column that is in the same ligne as 2015 in the database </div> </div> </div> 

 <?php $query = "SELECT * FROM publi where pub_type=0 order by pub_year DESC, pub_publi "; $result = mysqli_query($connection, $query); $previous =0; while ($val = mysqli_fetch_array($result)) { if ($previous <> $val['pub_year']) { $previous = $val['pub_year']; $year = $previous; echo $year; echo '<br>'; $Temp = highlight("person1",$val['pub_publi'],"0000FF"); $Temp = highlight("person2",$Temp,"0000FF"); $Temp = highlight("person3",$Temp,"0000FF"); $Temp = highlight("person4",$Temp,"0000FF"); $Temp = highlight("person5",$Temp,"0000FF"); $Temp = highlight("person6",$Temp,"0000FF"); $Temp = highlight("person7",$Temp,"0000FF"); $Temp = highlight("person8",$Temp,"0000FF"); $Temp = highlight("person9",$Temp,"0000FF"); $Temp = highlight("person10",$Temp,"0000FF"); echo '<a target=blank href="http://www.test.com/query.f?term=' . $val['pub_pubmed'] . '";)><img border="0" src="img/test.gif" align=MIDDLE alt="Search in for ' . $val['pub_publi'] . '"></a>'; echo $Temp; echo '<br>'; } } ?> 

It is outputing the years right

2016

2015

2014

etc...

but it is only showing the first ligne of each year not all the content for each year.

Answer 1

what u are asking is huge chunk to write. so here are steps:

1. create array with this SQL statement below and fetch assoc in PHP

   select distinct on year * from table

2. now use foreach($years as $year) on array and fetch content

   select content from table where year=$year

3. to sandwich your code output in SQL keep concatenating like

 $html = ""; $html .= "<div class=\\"all\\">"; foreach($years as $year){ $html .= "<div class=\\"content_$year\\">"; //then content fetched from second sql query $html .= "</div>"; } $html .= "</div>"; 

how to fetch data in sql | PHP.NET MANUAL

how to join/concat in php | PHP.NET MANUAL

LATER ADDITIONS, SNIPPET FROM MY OWN CODE :

$letter = $_POST['letter'];
$query_out = "SELECT link_id,singer_url FROM letter_mapping WHERE letter = '$letter'";
if($result_out = $conn_out->query($query_out)){
    if($result_out->num_rows > 0){
        while($row = $result_out->fetch_assoc()) {
            $link_id = $row['link_id'];
            $singer_url = $row['singer_url'];
            /*
            foreach($row as $name=>$value){
            }
            */
        }
    }
$result_out->free();
}
if($conn_out->close()){
    // Message for disconnect
    //echo "Status : DISCONNECTED<br/>";
}

Answer 2

1. Run the following query:

    Select Content From table order by year 

2. echo like following (or concat):

    while rs.hasNext(){ if (currentYear != lastyear){ echo div #with year As Class; } echo row # a single entry the way you want it dispalyed; lastYear = currentYear; }