[英]Javascript - sorting JSON object by a nested value
Summary : there is a multilevel parent-child comment system.ie 简介:有一个多层次的亲子评论系统
Example : 示例:
comment 1
comment 1-1
comment 1-1-1
comment 1-2
comment 1-2-1
comment 1-2-2
Here, comment 1
is parent and comment 1-1
& comment 1-2
both are child of comment 1
and so on.. 这里,
comment 1
是父母, comment 1-1
和comment 1-2
都是comment 1
孩子,依此类推。
Requirement : 要求:
we want to achieve the sorting
of whole object based on property value
.ie timestamp
(latest comment or reply will come on the top). 我们希望基于
property value
实现整个对象的sorting
。 timestamp
(最新评论或回复将在顶部)。
JSON Object : JSON对象:
{
"CommentText": "",
"CommentCreateStamp": "2016-03-22",
"Comments": [{
"CommentText": "comment 1",
"CommentCreateStamp": "2016-03-09",
"Comments": [{
"CommentText": "comment 1-1",
"CommentCreateStamp": "2016-03-15",
"Comments": [{
"CommentText": "comment 1-1-1",
"CommentCreateStamp": "2016-03-21",
"Comments": null
}]
}]
}],
"Comments": [{
"CommentText": "comment 2",
"CommentCreateStamp": "2016-03-12",
"Comments": [{
"CommentText": "comment 2-1",
"CommentCreateStamp": "2016-03-10",
"Comments": [{
"CommentText": "comment 2-1-1",
"CommentCreateStamp": "2016-03-14",
"Comments": null
}]
}]
}]
}
i tried so far : 我到目前为止尝试过:
JSfiddle : https://jsfiddle.net/asceeevb/ JSfiddle: https ://jsfiddle.net/asceeevb/
I seen lot of questions on stackoverflow but not working as per requirement. 我在stackoverflow上看到了很多问题,但没有按照要求工作。
Any immediate help will be highly appreciable. 任何直接的帮助都将非常值得注意。 Thanks
谢谢
I am not entirely sure what you are asking, but there a couple of things that seem wrong with your code: 我不完全确定你在问什么,但是你的代码中有一些看似错误的东西:
comments
property of the object, perhaps you wanted an array? comments
属性,也许你想要一个数组? Update: You were close, what you were missing were calls to sorting
for the nested comments. 更新:你很接近,你所缺少的是调用嵌套注释的
sorting
。 Here is a snippet that calls sorting
recursively: 这是一个递归调用
sorting
的片段:
var people = { "CommentText": "", "CommentCreateStamp": "", "Comments": [{ "CommentText": "c1", "CommentCreateStamp": "2016-03-23 06:05:36", "Comments": [{ "CommentText": "c2", "CommentCreateStamp": "2016-03-23 06:05:59", }], }, { "CommentText": "a1", "CommentCreateStamp": "2017-03-23 06:05:45", "Comments": [{ "CommentText": "a2", "CommentCreateStamp": "2016-03-23 06:06:05", }, { "CommentText": "a3", "CommentCreateStamp": "2016-03-23 06:06:16", }, { "CommentText": "a4", "CommentCreateStamp": "2016-03-23 06:06:23", }], }], }; function sorting(js_object, key_to_sort_by) { function sortByKey(a, b) { var x = a[key_to_sort_by]; var y = b[key_to_sort_by]; return ((x < y) ? 1 : ((x > y) ? -1 : 0)); }; js_object.sort(sortByKey); }; function sortComments(comments) { sorting(comments, 'CommentCreateStamp'); for (var i = 0; i < comments.length; i++) if (comments[i].hasOwnProperty('Comments')) sortComments(comments[i].Comments); }; sortComments(people.Comments); console.log(people.Comments);
You could make a flat array which keeps the reference and sort it by CommentCreateStamp
. 您可以创建一个平面数组来保留引用并通过
CommentCreateStamp
对其进行排序。
function getFlat(o) { this.push(o); Array.isArray(o.Comments) && o.Comments.forEach(getFlat.bind(this)); } var object = { "CommentText": "", "CommentCreateStamp": "2016-03-22", "Comments": [{ "CommentText": "comment 1", "CommentCreateStamp": "2016-03-18", "Comments": [{ "CommentText": "comment 1-1", "CommentCreateStamp": "2016-03-15", "Comments": [{ "CommentText": "comment 1-1-1", "CommentCreateStamp": "2016-03-21", "Comments": null }] }] }] }, flat = []; getFlat.bind(flat)(object); flat.sort(function (a, b) { return a.CommentCreateStamp.localeCompare(b.CommentCreateStamp); }); document.write('<pre>' + JSON.stringify(flat, 0, 4) + '</pre>');
Refining the @changed answer slightly -- I find that the following works pretty well: 稍微改进@changed的答案 - 我发现以下效果非常好:
export function sortObj(jsObj, sortKey,flgReverse) {
sortKey = sortKey.split(".");
let sk = '';
Object.keys(sortKey).forEach(function(key,idx){
sk += '[\'' + sortKey[key] + '\']';
});
function sortByKey(a, b) {
var x = eval("a" + sk);
var y = eval("b" + sk);
if(flgReverse) return ((x < y) ? -1 : ((x > y) ? 1 : 0));
else return ((x < y) ? 1 : ((x > y) ? -1 : 0));
};
return jsObj.sort(sortByKey);
};
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