按数字对文件进行排序

Question

I am new to python and trying to create a maths quiz program towards the end of the program I want to be able to print all the results in the file ( stored in the variable Reverseinfo) in numerical order. This doesn't seem to work , regardless of if I use the .sort function or the sorted() function. Any help would be appreciated, thanks

ReverseInfo already has scores and names put into the file

ReverseInfo= (score + (" ") + Name)

ClassANum=open("Class A Results High to Low.txt","a")
    ClassANum.write(ReverseInfo)
    ClassANum.write(" \n")
    ClassANum.close()

ClassBNum=open("Class B Results High to Low.txt","a")
    ClassBNum.write(ReverseInfo)
    ClassBNum.write(" \n")
    ClassBNum.close()

ClassCNum=open("Class C Results High to Low.txt","a")
    ClassCNum.write(ReverseInfo)
    ClassCNum.write(" \n")
    ClassCNum.close()


        if Viewscores=="Y":
            Classresults=input("Which Class would you like to see the results of?")

        if Classresults=="A":
            ClassA=open("Class A Results.txt","r")
            Class=ClassA
            alphabet=ClassA.readlines()
            for line in sorted(alphabet):
                print(line)

        elif Classresults=="B":
            ClassB=open("Class B Results.txt","r")
            Class=ClassB
            alphabet=ClassB.readlines()
            for line in sorted(alphabet):
                print(line)

        elif Classresults=="C":
            ClassC=open("Class C Results.txt","r")
            Class=ClassC
            alphabet=ClassC.readlines()
            for line in sorted(alphabet):
                print(line)

        else:
            print ("That is not valid")

        Numerical=input(" Do you want to see the results alphabetically?")

        if Numerical=="Y":
            NumClassresults=input("Which Class would you like to see the results of?")

        if NumClassresults=="A":
            ClassA=open("Class A Results High to Low.txt","r")
            Class=ClassA
            Hightolow=ClassA.readlines()
            for line in sorted(Hightolow):
                print(line)

        elif NumClassresults=="B":
            ClassA=open("Class B Results High to Low.txt","r")
            Class=ClassB
            Hightolow=ClassB.readlines()
            for line in sorted(Hightolow):
                print(line)

        if NumClassresults=="C":
            ClassA=open("Class C Results High to Low.txt","r")
            Class=ClassC
            Hightolow=ClassC.readlines()
            for line in sorted(Hightolow):
                print(line)

the data stored in Class A is: 10 Jamie 8 Jamie 8 Peter 10 Ham 4 Jack 10 Joseph 9 jamie 9 Yuan 9 Bob 10 John 6 Nash 8 John 10 josh 10 Honey

there is currently nothing stored in Class b file finally in class c: 9 jamie

9 Yuan

9 Bob

8 Peter

8 Jamie

4 Jack

10 Joseph

10 John

10 Jamie

10 Ham

Answer 1

Try below (assuming your file looks like Name 100 with many rows)

with open("Class C Results High to Low.txt","r") as f:
    lines = [(int(line.split(" ")[0]), line.split(" ")[1]) for line in f.readlines()]
    for l in sorted(lines, key=lambda score_name: score_name[0]):
        print l

Please let me know if there are any syntax errors (leave a comment), I couldn't test this - on the phone at the moment.

Answer 2

If the file is just lines with one integer per line, Hightolow will be a list of strings (that can be passed to int)

You need to pass a key function to sorted (or sort). In this case int does exactly what you need.

sorted(Hightolow, key=int)

ie use it in the loop like this:

for line in sorted(Hightolow, key=int):

Alternatively you can make Hightolow a list of ints as you read the file

Hightolow = [int(x) for x in ClassA]