如何将 YY/MM/DD 类型的字符串转换为 java.util.Date？

Question

I have searched but did not find the exact format(YY/MM/DD) for parsing the String.

How can I convert a string of type YY/MM/DD to java.util.Date . I have strings in the format "160310", "160211".

Answer 1

You can use SimpleDateFormat for this.

String target = "160211";
DateFormat df = new SimpleDateFormat("yyMMdd", Locale.ENGLISH);
Date result =  df.parse(target);

For more options and info you can always checkout the full documentation about it here: http://docs.oracle.com/javase/8/docs/api/java/text/SimpleDateFormat.html

Answer 2

Nit: The format isn't "YY/MM/DD", it's "YYMMDD" (note the slashes). Regardless, you can use a SimpleDateFormat to parse such strings:

DateFormat df = new SimpleDateFormat("yyMMdd");
Date date = df.parse("160211");

Answer 3

Use the following code , It will

    String mydate="160310";
    SimpleDateFormat sd=new SimpleDateFormat("YYmmdd",Locale.ENGLISH);
    Date date = sd.parse(mydate);
    System.out.println(date);`

Answer 4

If you have reached the area of Java 8, you might also consider

        Date dt = Date.valueOf(LocalDate.from(DateTimeFormatter.ofPattern("yyMMdd").parse("160123")));

But in fact, you would not do the conversion to the old ugly date if you can avoid it, but rather go along with the LocalDate you created on your way.

Answer 5

Like this:

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class DateTester {

    public static void main(String[] args) {
        SimpleDateFormat sdf = new SimpleDateFormat("yyMMdd");

        Date date = null;
        try {
            date = sdf.parse("160310");
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        System.out.println(date);
    }
}