Python Errno13权限被拒绝

Question

I'm getting a permission denied error when trying to use glob to get a filename list and csv to open csv files for dictionary reading. Here is my code:

import csv
import glob

#Filepath variable for the CSV files
path = "C:\\Users\\josh\\Data"

for filename in glob.glob(path):
    with open(filename) as csv_file:
        for row in csv.DictReader(csv_file):
            print row

I've tried running some file opening tests with the following code and it works perfectly. So I know I can open, read, write to this folder:

open('C:\\Users\\josh\\Data\\testing.txt', 'w').write('this is a test')
open('C:\\Users\\josh\\Data\\03142016.csv')

Lastly, here is the full traceback if that helps:

Traceback (most recent call last):

  File "<ipython-input-10-49215e5eb704>", line 1, in <module>
    runfile('C:/Users/josh/.spyder2/csvparser2.0.py', wdir='C:/Users/josh/.spyder2')

  File "C:\Anaconda\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 580, in runfile
    execfile(filename, namespace)

  File "C:/Users/josh/.spyder2/csvparser2.0.py", line 41, in <module>
    with open(filename) as csv_file:

IOError: [Errno 13] Permission denied: 'C:\\Users\\josh\\Data'

Any ideas? Thank you for your help.

Answer 1

Right now you're doing:

path = "C:\\Users\\josh\\Data"

for filename in glob.glob(path):

glob.glob() on only a pathname without any special globbing characters ( * , ? , etc) will just return that pathname. In this case the directory name, which you're not allowed to open() since that doesn't make a lot of sense.

You probably intended to write:

glob.glob(path + '\\*'):

or:

glob.glob(path + '\\*.csv'):

Bonus tip

You already figured out that using open('C:\\\\Users\\\\josh\\\\Data\\\\03142016.csv') works fine, which is a good first step in solving the problem. You could have found out the error by using basic "printf-debugging":

path = "C:\\Users\\josh\\Data"

for filename in glob.glob(path):
    print(filename)
    with open(filename) as csv_file:
        [.. trim ..]

This would have printed out C:\\\\Users\\\\josh\\\\Data , and not C:\\\\Users\\\\josh\\\\Data\\\\03142016.csv :-)

Lesson: when in doubt, print() out as many values as you can, and check if they're what you expect ;-)