仅在MyISAM表中更改mysql中的表

Question

I am trying to convert all mysql MyISAM tables to InnoDB without pick the already in InnoDB.

I have 6734 rows (tables in MyISAM format) using this query:

SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE engine = 'MyISAM';

And I have 11218 rows (tables in InnoDB format) using this query:

SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE engine = 'InnoDB';

So I want connect each result of tables in MyISAM for pass only as subquery:

ALTER TABLE table_name ENGINE = InnoDB;

How this can be achieved? select subquery? My purpose is avoid to process the already converted to innodb because it will take a lot more time if I make a script as the following:

for db in `echo "show databases"| mysql`;
do
echo $db

echo 'SHOW TABLES;' \
 | mysql -D $db \
 | awk '!/^Tables_in_/ {print "ALTER TABLE `"$0"` ENGINE = InnoDB;"}' \
 | column -t \
 | mysql -D $db
echo 'finish';
done;

Answer 1

You can direct create the ALTER statements in SQL. if you have more SCHEMAS to ignore you can add them in the IN clause.

SELECT
  CONCAT ('ALTER TABLE `',TABLE_SCHEMA, '`.`' ,TABLE_NAME,'` ENGINE = InnoDB;') as newsql
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_TYPE = 'BASE TABLE'
  AND TABLE_SCHEMA NOT IN ('mysql')
  AND `ENGINE` = 'MYISAM';

To use with shell:

echo "SELECT CONCAT ('ALTER TABLE \`',TABLE_SCHEMA, '\`.\`' ,TABLE_NAME,'\` ENGINE = InnoDB;')  FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_TYPE = 'BASE TABLE' AND TABLE_SCHEMA NOT IN ('mysql') AND \`ENGINE\` = 'MYISAM';" |mysql --skip-column-names |mysql