std :: cout << x之间的差异是什么？ 和std :: cout <

Question

I'm a newbie to programming, I started teaching myself yesterday, I've been getting everything but I honestly, do not understand the difference between

std::cout << x;

and

std::cout << x << std::endl;

Nobody has explained this to me, and I'm asking to stay on the safe side.

Answer 1

endl writes a new-line to the stream, so subsequent output will appear on the next line. It also flushes the stream's buffer, usually causing a slow-down .

This flushing means that 99% of the time, endl is a mistake, and you should just write "\\n" (or '\\n' ) instead. When you really do want to flush the stream, I think it's better to make that explicit by invoking std::flush instead:

std::cout << x << '\n' << std::flush;

As far as run-time actions goes, this is equivalent to using std::endl , but in terms of making your intent clear, it's drastically superior.

Answer 2

The std::endl adds a newline code to a stream and also flushes the output buffer and std::cout << x is just printing x . So if you got a code

cout << 5;
cout << 5;

it will be

55

as an output, but if you add a endl to a first cout the output will be

5

5

What i really recommend you is to use '\\n' it is much more better than endl.