使用 PHP 的 DOMDocument 解析 html 内容时出错

Question

Can anyone please help me in finding out what have I done wrong in the code given below.

I have a PHP variable named whose value is the following html...

<p><img src="./images/image1.jpeg" alt=""></p>

This value for variable is obtained from a database query.

The function below creates a DOMDocument object using the variable :

public function convert_to_tinymce_data($news_content)
{
    $dom=new DOMDocument();

    $dom->loadHTML($news_content);

    $img_nodes=$dom->getElementsByTagName('img');

    foreach($img_nodes as $link)
    {
        $img_link=$link->getAttribute('src');

        echo $link->getAttribute('src');

    }
}

But nothing is being echoed (receiving a blank page).

Answer 1

I've tryed this code and it works:

$n = '<p><img src="./images/image1.jpeg" alt=""></p>';

function convert_to_tinymce_data($news_content){
 $dom=new DOMDocument();

 $dom->loadHTML($news_content);
 $img_nodes=$dom->getElementsByTagName('img');

 foreach($img_nodes as $link) {
        $img_link=$link->getAttribute('src');
        echo $img_link;
  }
}

convert_to_tinymce_data($n);

I see you have public function , but I don't see class. If it's global function, not a method of a class, that's the reason why it doesn't work. Or you don't call function properly.

(What you have there is function definition... it executes after you call it... Having same variable names in your function's definition and outside is bad practice and can be easily turn into problem)

Just to add: Check you're error_log file and let us know is there something interesting in it...