如何在 ListView C# 中随机排列项目？

Question

I am making a very simple MP3, WAV, and WMA media player.

The music files are listed within a listView consisting of two columns (Column 1: Audio Title, Column 2: File Location).

I would like to create a button that will shuffle and randomize ALL of the items that are in the list view.

Here's an example:

Title    Location
SONG1    C:\\A LOCATION
SONG2    "
SONG3    "
SONG4    "
SONG5    "
SONG6    "

into this:

Title    Location
SONG6    C:\\A LOCATION
SONG3    "
SONG4    "
SONG2    "
SONG1    "
SONG5    "

I'm using axMediaPlayer (.wmp)

Thank you for the help! :)

Answer 1

Random rnd = new Random();
var randomizedList = from item in listbox.Items
                     orderby rnd.Next()
                     select item;

Then assign the randomizedList back to the listbox

or

private static Random rng = new Random();  

public static void Shuffle<T>(this IList<T> list)  
{  
    int n = list.Count;  
    while (n > 1) {  
        n--;  
        int k = rng.Next(n + 1);  
        T value = list[k];  
        list[k] = list[n];  
        list[n] = value;  
    }  
}

Usage:

var products = listview.Items.ToList();
products.Shuffle();

Answer 2

using System;
using System.Collections;
using System.Windows.Forms;

public static class ListViewExtensions
{
    public static void Randomize(this ListView lv)
    {
        ListView.ListViewItemCollection list = lv.Items;
        Random rng = new Random();
        int n = list.Count;
        lv.BeginUpdate();
        while (n > 1)
        {
            n--;
            int k = rng.Next(n + 1);
            ListViewItem value1 = (ListViewItem)list[k];
            ListViewItem value2 = (ListViewItem)list[n];
            list[k] = new ListViewItem();
            list[n] = new ListViewItem();
            list[k] = value2;
            list[n] = value1;
        }
        lv.EndUpdate();
        lv.Invalidate();
    }
}