即使该方法引发代码400异常，PHP curl也会返回代码200

Question

I've done an API and now I'm trying to make calls using the curl method and I'm trying to input bad data to get the errors and check all works well. But what I don't understand is why the curl call returns the code 200 when the input data is wrong and it throws an exception with code 400.

That's my curl call:

public function test() {

    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL,"http://127.0.0.1/mysite/public/rest/createUser/");
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS, [
        "email" => "some.email",
        "address" => "elm street",
        "telephone" => "123123123",
    ]);

    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $server_output = curl_exec ($ch);

    curl_close ($ch);

    var_dump($server_output);

}

In that case the email is not valid and the exception is thrown when calling the createUser method and shows.

{"error":"The email asd2123123 is invalid"}

And the code is 200 instead of 400

If I call the URL and I don't use the curl method it returns the code 400

Also I'm using Postman to make the calls and it returns the code 400 if I call directly to createUser and I put an invalid e-mail.

Answer 1

Try your code that way :

public function test() {

    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL,"http://127.0.0.1/mysite/public/rest/createUser/");
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS, [
        "email" => "some.email",
        "address" => "elm street",
        "telephone" => "123123123",
    ]);

    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_HEADER, true);    // we want headers
    $server_output = curl_exec ($ch);

    curl_close ($ch);
    $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
    echo 'HTTP code: ' . $httpcode;
    var_dump($server_output);
}

Is the HTTP code still 200 ?