来自BASHRC的解析功能

Question

I'm using BASHRC to store alot of my daily routines, and overtime its gotten cluttered, and now there are some duplicate. Was wondering if there's a way with SED\\AWK\\grep to parse all of the functions into array and then remove duplicate.

sample of bashrc with duplicate:

  function action1(){
    /usr/bin/operate $1
    }
   function action2(){
    /usr/bin/perform $1 $2
    }
   function action1(){
    /usr/bin/operate $1
    }

Thanks,

Roy

Answer 1

If that's REALLY what your input file looks like then all you need is:

$ awk '$1=="function"{unq=!seen[$2]++} unq' file
  function action1(){
    /usr/bin/operate $1
    }
   function action2(){
    /usr/bin/perform $1 $2
    }

If it's not then edit your question to provide some truly representative sample input and expected output.