[英]How to search JSON array in MySQL?
Let's say I have a JSON column named data in some MySQL table, and this column is a single array .假设我在某个 MySQL 表中有一个名为data的 JSON 列,并且该列是一个数组。 So, for example, data may contain:
因此,例如,数据可能包含:
[1,2,3,4,5]
[1,2,3,4,5]
Now I want to select all rows which have a data column where one of its array elements is greater than 2. Is this possible?现在我想要 select 所有具有数据列的行,其中一个数组元素大于 2。这可能吗?
I tried the following, but seems it is always true regardless of the values in the array:我尝试了以下方法,但无论数组中的值如何,它似乎总是正确的:
SELECT * from my_table
WHERE JSON_EXTRACT(data, '$[*]') > 2;
You may search an array of integers as follows:您可以按如下方式搜索整数数组:
JSON_CONTAINS('[1,2,3,4,5]','7','$') Returns: 0
JSON_CONTAINS('[1,2,3,4,5]','1','$') Returns: 1
You may search an array of strings as follows:您可以按如下方式搜索字符串数组:
JSON_CONTAINS('["a","2","c","4","x"]','"x"','$') Returns: 1
JSON_CONTAINS('["1","2","3","4","5"]','"7"','$') Returns: 0
Note: JSON_CONTAINS returns either 1 or 0注意:JSON_CONTAINS 返回 1 或 0
In your case you may search using a query like so:在您的情况下,您可以使用如下查询进行搜索:
SELECT * from my_table
WHERE JSON_CONTAINS(data, '2', '$');
SELECT JSON_SEARCH('["1","2","3","4","5"]', 'one', "2") is not null
is true是真的
SELECT JSON_SEARCH('["1","2","3","4","5"]', 'one', "6") is not null
is false是假的
I don't know if we found the solution.我不知道我们是否找到了解决方案。 I found with MariaDB a way, to search path in a array.
我用 MariaDB 找到了一种在数组中搜索路径的方法。 For example, in array
[{"id":1}, {"id":2}]
, I want find path with id equal to 2.例如,在数组
[{"id":1}, {"id":2}]
,我想找到 id 等于 2 的路径。
SELECT JSON_SEARCH('name_field', 'one', 2, null, '$[*].id')
FROM name_table
The result is:结果是:
"$[1].id"
The asterisk indicate searching the entire array星号表示搜索整个数组
Since MySQL 8 there is a new function called JSON_TABLE . 从 MySQL 8 开始,有一个名为JSON_TABLE的新函数。
CREATE TABLE my_table (id INT, data JSON);
INSERT INTO my_table VALUES
(1, "[1,2,3,4,5]"),
(2, "[0,1,2]"),
(3, "[3,4,-10]"),
(4, "[-1,-2,0]");
SELECT DISTINCT my_table.*
FROM my_table, JSON_TABLE(data, "$[*]" COLUMNS(nr INT PATH '$')) as ids
WHERE ids.nr > 2;
+------+-----------------+
| id | data |
+------+-----------------+
| 1 | [1, 2, 3, 4, 5] |
| 3 | [3, 4, -10] |
+------+-----------------+
2 rows in set (0.00 sec)
A possible way is to deal with the problem as string matching.一种可能的方法是将问题作为字符串匹配来处理。 Convert the JSON to string and match.
将 JSON 转换为字符串并匹配。
Or you can use JSON_CONTAINS .或者您可以使用JSON_CONTAINS 。
You can use JSON extract to search and select data您可以使用 JSON 提取来搜索和选择数据
SELECT data, data->"$.id" as selectdata
FROM table
WHERE JSON_EXTRACT(data, "$.id") = '123'
#ORDER BY c->"$.name";
limit 10 ;
我使用 JSON_EXTRACT 和 JSON_CONTAINS (MariaDB) 的组合:
SELECT * FROM table WHERE JSON_CONTAINS(JSON_EXTRACT(json_field, '$[*].id'), 11, '$');
SET @doc = '[{"SongLabels": [{"SongLabelId": "111", "SongLabelName": "Funk"}, {"SongLabelId": "222", "SongLabelName": "RnB"}], "SongLabelCategoryId": "test11", "SongLabelCategoryName": "曲风"}]';
SELECT *, JSON_SEARCH(@doc, 'one', '%un%', null, '$[*].SongLabels[*].SongLabelName')FROM t_music_song_label_relation;
result: "$[0].SongLabels[0].SongLabelName"结果:“$[0].SongLabels[0].SongLabelName”
SELECT song_label_content->'$[*].SongLabels[*].SongLabelName' FROM t_music_song_label_relation;
result: ["Funk", "RnB"]结果:[“放克”,“RnB”]
I have similar problem, search via function我有类似的问题,通过函数搜索
create function searchGT(threshold int, d JSON)
returns int
begin
set @i = 0;
while @i < json_length(d) do
if json_extract(d, CONCAT('$[', @i, ']')) > threshold then
return json_extract(d, CONCAT('$[', @i, ']'));
end if;
set @i = @i + 1;
end while;
return null;
end;
select searchGT(3, CAST('[1,10,20]' AS JSON));
This example works for me with mysql 5.7
above这个例子适用于我上面的 mysql
5.7
SET @j = '{"a": [ "8428341ffffffff", "8428343ffffffff", "8428345ffffffff", "8428347ffffffff","8428349ffffffff", "842834bffffffff", "842834dffffffff"], "b": 2, "c": {"d": 4}}';
select JSON_CONTAINS(JSON_EXTRACT(@j , '$.a'),'"8428341ffffffff"','$') => returns 1
notice about "
around search keyword, '"8428341ffffffff"'
注意
"
围绕搜索关键字, '"8428341ffffffff"'
This seems to be possible with to JSON_TABLE
function. It's available in mysql version 8.0 or mariadb version 10.6.这似乎可以用于
JSON_TABLE
function。它在 mysql 版本 8.0 或 mariadb 版本 10.6 中可用。
With this test setup使用此测试设置
CREATE TEMPORARY TABLE mytable
WITH data(a,json) AS (VALUES ('a','[1]'),
('b','[1,2]'),
('c','[1,2,3]'),
('d','[1,2,3,4]'))
SELECT * from data;
we get the following table我们得到下表
+---+-----------+
| a | json |
+---+-----------+
| a | [1] |
| b | [1,2] |
| c | [1,2,3] |
| d | [1,2,3,4] |
+---+-----------+
It's possible to select every row from mytable wich has a value greater than 2 in the json array with this query. select mytable 中的每一行都可以使用此查询在 json 数组中具有大于 2 的值。
SELECT * FROM mytable
WHERE TRUE IN (SELECT val > 2
FROM JSON_TABLE(json,'$[*]'
columns (val INT(1) path '$')
) as json
)
Returns:退货:
+---+-----------+
| a | json |
+---+-----------+
| c | [1,2,3] |
| d | [1,2,3,4] |
+---+-----------+
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