使用sed提取带有特殊字符的两个单词之间的整个字符串

Question

I have a file with each line in the format:

<tr><td>20456712 </td><td>Alin Smith </td><td.....(and so on).

I want to return all studens names and their ID's in lines, output should be:

20456712 Alin Smith

.....

How can I do it with sed/grep?.

I've tried many things to get whats between <tr><td> and </td><td> but nothing worked because of the special characters I think.

I'm already a few days trying with no results.

I've tried => sed -r 's/.*[<]+tr+[>]+[<]+td+[>](\\S+).* <\\/td><td>(\\S+).*/\\1 \\2/' , but it only gave me ID + the first name: 20456712 Alin

Answer 1

You could try this RegEx:

<tr><td>([\d\s]+)<\/td><td>([\w\s]+)<\/td>

All the data will be stored in Group 1 (the ID) and Group 2 (the Full Name). You can see this in the demo by hovering over the match and checing the data in both groups

Live Demo on RegExr

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How it works:

<tr>         # Opening <tr>
<td>         # Opening <td>
([\d\s]+)    # ID
<\/td>       # Closing </td>
<td>         # Opening <td>
([\w\s]+)    # Full Name
<\/td>       # Closing </td>

Answer 2

This should also help you out:

sed 's/.*\([0-9]\{8\}\) <\/td><td>\([^<]*\) .*/\1 \2/'

View test on the command line