mysql 按最后一条记录分组并在最后一条记录中查找备注

Question

sorry miss some column my table is and data:

tablename = tbreport

comcode, user_id, comname, remark, date

0010066, 32, Wicam, NotInterest, 2014-02-01 0010066, 32, Wicam, Discusing, 2014-02-05 0010066, 32, Wicam, Interest, 2014-02-08 0010066, 32, Wicam, Pending , 2014-02-21 0010596, 32, United, Interest, 2014-02-08 0010606, 32, SEACAM, NotInterest ,2014-03-08 0040025, 16, SkyView, Interest , 2014-03-17

I use query below:

$uer_id='$_GET[user_id]'; $remark='$_GET[remark]'; $query = $link->query("SELECT * FROM (SELECT *FROM tbreport where user_id='$uid' ORDER by date DESC ) tbreport GROUP BY comcode");

the result show the last record :

---

comcode, user_id, comname, remark, date

0010066, 32, Wicam, Pending , 2014-02-21 0010596, 32, United, Interest, 2014-02-08
0010606, 32, SEACAM, NotInterest ,2014-03-08 0040025, 32, SkyView, Interest ,2014-03-17

what I need the result like this

when $remark = 'Interest' should show like below

comcode, user_id, comname, remark, date

0010596, 32, United, Interest, 2014-02-08
0040025, 32, SkyView, Interest ,2014-03-17

And when $remark= 'Pending' should show like below

---

comcode, user_id, comname, remark, date

0010066, 32, Wicam, Pending , 2014-02-21

so how would I do more? Thanks, if have any query Sary

Answer 1

SELECT m1.* FROM tbreport m1 LEFT JOIN tbreport m2 
ON (m1. comname = m2. comname AND m1.date < m2.date) 
WHERE m2.date IS NULL and m1.remark='$remark';