[英]Passing a struct item as the parameter
I understand it is possible to pass a struct as an argument etc. 我知道可以将结构作为参数传递。
But is it possible to have the parameter preset so only a specific struct item can be passed such: 但是是否可以预先设置参数,以便只能传递特定的结构项,例如:
struct inventory* searchForItem(struct stockItem.componentType code){
I'm getting : error: expected ';' 我得到:错误:预期为';' , ', ' before token ,','在令牌之前
EDIT: 编辑:
typedef struct stockItem {
char *componentType;
char *stockCode;
int numOfItems;
int price;
} stockItem;
The type of that component is char *
, so just make that the type of the parameter. 该组件的类型为char *
,因此只需使该参数为类型即可。
struct inventory* searchForItem(char *code){
If you want to make the type more strict, make a typedef for the field in question: 如果要使类型更严格,请为相关字段创建一个typedef:
typedef char * stockItem_componentType;
typedef struct stockItem {
stockItem_componentType componentType;
char *stockCode;
int numOfItems;
int price;
} stockItem;
struct inventory* searchForItem(stockItem_componentType code){
Note that this hides a pointer behind a typedef
which is not recommended. 请注意,这会将指针隐藏在typedef
后面,这是不推荐的。 Then people reading your code (including yourself) won't know just by looking at it that it's a pointer, which can lead to confusion. 这样一来,阅读您的代码(包括您自己)的人们就不会仅仅通过查看它的指针就知道它是一个指针,这可能导致混乱。
(Since the comments on the other answer are too constrained) (由于对其他答案的评论过于局限)
First you define a new type for componentType
, like this: 首先,为componentType
定义一个新类型,如下所示:
typedef char *stockItem_componentType; // Naming subject to conventions
Now in your structure, you use this type instead of simple char*
. 现在在您的结构中,您将使用此类型而不是简单的char*
。 This is optional, but very much recommended. 这是可选的,但是非常推荐。 Like this: 像这样:
typedef struct stockItem {
stockItem_componentType componentType;
char *stockCode;
int numOfItems;
int price;
} stockItem;
And finally, your function prototype is: 最后,您的函数原型是:
struct inventory* searchForItem(stockItem_componentType code);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.