ReactJS，Redux：如何在STATE中返回一组项目？

Question

I'm having trouble getting back then 1 array item in the results returned from an api call.

This is the function in actions.

  followCheckList:function(userId){
    for(var i= 0; i < userId.length;i++ ){
      return{
        types: [C.FOLLOW_CHECK_LIST, C.FOLLOW_CHECK_LIST_SUCCESS, C.FOLLOW_CHECK_LIST_FAIL],
        promise: (client)=> client.get(`/graph/me/follows/${userId[i]}`)
        .then(result => {
          return result.id;      
        })
      }
    }
  }

My reducers

    case C.FOLLOW_CHECK_LIST:
        return{
            ...state,
            follow_check_list:null,
            error:false,
        };
    case C.FOLLOW_CHECK_LIST_SUCCESS:
        return{
            ...state,
            //break here
            error:false,                
            follow_check_list: action.result
        };

    case C.FOLLOW_CHECK_LIST_FAIL:
        return{
            ...state,
            follow_check_list:false,
            error:action.error,
        };

    default: return state || {loading: false,
                                    loaded: null,
                                    list_loaded: null};
}

I'm expecting 2 results from follow_check_list : action.result so in my state I should see

follow_check_list : Array[2].
       0: item1,
       1: item2

But instead I see :

follow_check_list : Array[1].
       0: item1,

update My component. arrayIds has 2 items.

let arrayIds=[];
const FollowStatus = React.createClass ({

    componentWillMount(){
        arrayIds.push(this.props.status);
    },
    componentDidMount(){
        this.props.followCheckList(arrayIds)
    },

Thanks in advance guys

Answer 1

看起来您的followCheckList函数在“ for”循环中有一个“ return”语句：该函数的执行在第一次迭代时停止，这一定是为什么只得到“ item1”的原因。