[英]Change scenario in form Yii2
I want to change scenario in view page by jQuery. 我想通过jQuery更改视图页面中的方案。 There is a checkbox in my form, I want inputbox be required in checked checkbox. 我的表单中有一个复选框,我希望选中的复选框中需要输入框。
my rule: 我的规则:
public function rules() {
return [
.
.
.
['pass' , 'required', 'on'=> 'checked']
]
}
my view page: 我的查看页面:
<?=$form->field($model, 'check')->checkbox()?>
<?=$form->field($model, 'Pass')->textInput(['maxlength' => 20])?>
Try to set up your rule like this: 尝试像这样设置您的规则:
public function rules() {
$checkBoxID = Html::getInputId($this, 'check');
return [
/* other rules */
['pass' , 'required',
'when' => function($model) {
return $model->check;
},
'whenClient'=> "function(attribute, value){
return $('#{$checkBoxID}').prop('checked');
}",
'on' => 'checked'
],
];
}
Read about conditional validation and whenClient validator property . 阅读有关条件验证和whenClient validateator属性的信息 。 Also consider naming you scenario more informative, eg by its purpose, like 'on' => 'sign-up'
, or 'on' => 'login'
. 还可以考虑给您的场景命名更多信息,例如,按其目的命名,例如'on' => 'sign-up'
或'on' => 'login'
。 Scenario is useful when you need certain rules to apply in particular cases, but you need to specify this scenario explicitly. 当您需要在某些情况下应用某些规则但需要显式指定此方案时,方案非常有用。 Either when you instantiate a model 实例化模型时
$model = new MyModel();
$model->scenario = 'sign-up';
and passing it into a view, or before doing any validation after $model->load($data)
并将其传递到视图中,或者在$model->load($data)
之后进行任何验证之前
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