[英]Integrity constraint violation using factory relationships in laravel 5.2
I am new to testing in laravel and I'm trying to create dummy data using Model Factories. 我是在laravel中进行测试的新手,我正在尝试使用模型工厂创建虚拟数据。 I have three tables: 我有三个表:
A firm has many clients and a client has many briefs. 一个公司有很多客户,一个客户有很多简介。 The format of clients
and briefs
is very similar. clients
和briefs
的格式非常相似。 They both have foreign keys firm_id
and client_id
respectfully. 它们都分别具有外键firm_id
和client_id
。 Whilst doing a phpunit test I want to create an instance of a client from a firm and an instance of a brief from the client using the following code: 在进行phpunit测试的同时,我想使用以下代码创建一个公司的客户实例和一个客户的摘要实例:
$client = $firm->clients()
->save(factory(App\SearchFirmClient::class)->create());
$brief = $client->briefs()
->save(factory(App\SearchFirmBrief::class)->create());
$client
is created without a fuss but $brief
throws up an error: $client
创建时没有大惊小怪,但是$brief
引发错误:
Illuminate\Database\QueryException: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'client_id' cannot be null (SQL: insert into `search_firms_briefs` (`user_id`, `title`, `description`, `contact_id`, `client_id`, `updated_at`, `created_at`) values (1, Et in amet., Quo soluta ut impedit nesciunt autem. Laborum aperiam est non molestiae animi non quod. Explicabo eligendi doloribus ex quia vitae placeat ut., 0, , 2016-03-30 10:06:34, 2016-03-30 10:06:34))
The formats of both tables: 这两个表的格式:
Schema::create('search_firms_clients', function(Blueprint $table)
{
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')->references('id')->on('search_firms')->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
});
Schema::create('search_firms_briefs', function(Blueprint $table)
{
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
});
The model factory for each: 每个模型工厂:
$factory->define(App\SearchFirmClient::class, function ($faker) {
return [
'name' => $faker->company,
'email' => $faker->companyEmail,
'phone' => $faker->phoneNumber,
'address' => $faker->address,
'website' => $faker->url,
];
});
$factory->define(App\SearchFirmBrief::class, function ($faker) {
return [
'user_id' => 1,
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
});
The relationships: 关系:
class SearchFirm extends Model
{
protected $table = 'search_firms';
protected $primaryKey = 'id';
public function clients() {
return $this->hasMany('SearchFirmClient', 'search_firm_id');
}
}
class SearchFirmClient extends Model
{
use SoftDeletes;
protected $table = 'search_firms_clients';
protected $primaryKey = 'client_id';
protected $dates = [ 'deleted_at' ];
public function briefs()
{
return $this->hasMany('SearchFirmBrief', 'client_id')->orderBy( 'updated_at', 'desc');
}
}
class SearchFirmBrief extends Model
{
use SoftDeletes;
protected $table = 'search_firms_briefs';
protected $primaryKey = 'brief_id';
protected $touches = array('client');
protected $dates = [ 'deleted_at'];
public function client() {
return $this->belongsTo('SearchFirmClient', 'client_id');
}
}
Issue #1 第1期
There is no id
column on the briefs
table, but you are referencing it on the clients
table. briefs
表上没有id
列,但是您在clients
表上引用了它。
Change the foreign key to brief_id
: 将外键更改为brief_id
:
Schema::create('search_firms_clients', function(Blueprint $table)
{
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')
->references('brief_id') // <-- Change this
->on('search_firms')
->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
});
Schema::create('search_firms_briefs', function(Blueprint $table)
{
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
});
Issue #2 第2期
You don't have a user_id
member. 您没有user_id
成员。
$factory->define(App\SearchFirmBrief::class, function ($faker) {
return [
'client_id' => 1, // <-- change this
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
});
Conclusion 结论
It would be best if you follow Laravel's naming standards, it will save you a lot of headache in the future (ie use default table names, primary key names) 如果您遵循Laravel的命名标准,那将是最好的选择,它将在以后为您省去很多麻烦(例如,使用默认表名,主键名)
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