如何在log4j（版本1.2.17）中转义stacktrace

Question

I have the following code:

try {
   ...
} catch (Exception e) {
    log.error( "failed!", e );
}

How can I escape stacktrace?

I want escape " with /"

and \\ with \\\\

I use log4j 1.2.17 version. and properties file configuration.

update

current configuration:

log4j.rootLogger=WARN,console
log4j.appender.console=org.apache.log4j.ConsoleAppender
log4j.appender.console.layout=org.apache.log4j.EnhancedPatternLayout
log4j.appender.console.layout.ConversionPattern=%d{EEE, dd MMM yyyy HH:mm:ss,SSS z} %-5p [%t] %c{1.}#%M:%L - %m%n
log4j.logger.com.hazelcast=INFO

Answer 1

public class EscapedEnhancedPatternLayout extends EnhancedPatternLayout {
    @Override
    public String format(LoggingEvent event) {
        return StringEscapeUtils.escapeJava(super.format(event));
    }
}