如何检查另一个数组中是否存在数组键的值？

Question

I can do this:

filter(lambda x: x.key1 in ["aa", "bb", "cc"], [{key1: ..., key2: ...}, {key1: ...}])

How can I do the opposite thing?

dict_items = [{key1: ..., key2: ...}, {key1: ...}]
filter(lambda x: x in ???dict_items.key1???, ["aa", "bb", "cc"])

Answer 1

Assuming you have two dicts d1 = {key1: val1, key2: val2 } and d2 = {key3: val3, key4: val4}

It's not clear what you are trying to compare but if you want to compare keys just type:

set.intersection(set(d1.keys()), set(d2.keys()))

For values:

set.intersection(set(d1.values()), set(d2.values()))

Answer 2

use can use list comprehension as follows:

a = {"aa":1, "ll":4}
b = {"bb": 'pl', "xx":12, "qq": 66}
print [key for j in [a, b] for key, val in j.iteritems() if key in ["aa", "bb", "cc"]]

Or if you only require keys u can use:

print [key for j in [a, b] for key in j.keys() if key in ["aa", "bb", "cc"]]

output:

['aa', 'bb']