[英]jCanvas - background image disappears
im use this http://projects.calebevans.me/jcanvas/ and im have simple example我使用这个http://projects.calebvans.me/jcanvas/并且我有简单的例子
<input type="button" class="bt" value="draw"/><br>
<canvas id="picture" width=1350 height=1350></canvas>
and js和js
var canvas = document.getElementById("picture");
var ctx = canvas.getContext('2d');
var img = new Image();
img.src = "tank_usa.jpg";
img.onload = function(){
ctx.drawImage(img, 0, 0);
}
$(".bt").on("click",function(){
// Draw a resizable image
$('#picture').addLayer({
type: 'image',
draggable: true,
source: 'facesSmall.png',
fillStyle: '#fff',
strokeStyle: '#c33',
strokeWidth: 2,
x: 180, y: 150,
width: 200, height: 125,
handle: {
type: 'arc',
fillStyle: '#fff',
strokeStyle: '#c33',
strokeWidth: 2,
radius: 10
}
})
.drawLayer();
})
if im click on button bt,and hover canvas div, my background disappears how i can do what new image draw over background如果我点击按钮 bt,然后悬停画布 div,我的背景就会消失,我该如何在背景上绘制新图像
Your background gets erased because you are using ctx.drawImage
, which does not create a jCanvas layer.您的背景被擦除,因为您使用的是
ctx.drawImage
,它不会创建 jCanvas 层。 jCanvas layers and non-layers cannot exist on the same canvas, because when jCanvas redraws the canvas (manually via drawLayers()
or automatically when events are triggered), non-layers will be erased. jCanvas 图层和非图层不能存在于同一个画布上,因为当 jCanvas 重绘画布时(通过
drawLayers()
手动或触发事件时自动),非图层将被擦除。
To fix this, simply draw "tank_usa.jpg"
like you drew 'facesSmall.png'
: using addLayer
with type: 'image'
set.为了解决这个问题,简单地得出
"tank_usa.jpg"
像你画'facesSmall.png'
:使用addLayer
与type: 'image'
集。
$('#picture').addLayer({
type: 'image',
source: 'tank_usa.jpg',
x: 0, y: 0,
fromCenter: false
});
$(".bt").on("click",function(){
// Draw a resizable image
$('#picture').addLayer({
type: 'image',
draggable: true,
source: 'facesSmall.png',
fillStyle: '#fff',
strokeStyle: '#c33',
strokeWidth: 2,
x: 180, y: 150,
width: 200, height: 125,
handle: {
type: 'arc',
fillStyle: '#fff',
strokeStyle: '#c33',
strokeWidth: 2,
radius: 10
}
})
.drawLayer();
});
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