[英]Multidimensional Array - Get unique values, but count all duplicates
I have a multi-dimensional array that I would like to get unique sub-values from, but also have a count of how many times those unique sub-values occurred. 我有一个多维数组,我想从中获取唯一的子值,但是还要计算这些唯一的子值出现了多少次。
For instance, this would be my starting array: 例如,这将是我的起始数组:
[0] => Array
(
[0] => Array
(
[id] => 1533438473619168
)
[1] => Array
(
[id] => 3333333333333333
)
)
[1] => Array
(
[0] => Array
(
[id] => 1533438473619168
)
[1] => Array
(
[id] => 5555555555555555
)
)
[2] => Array
(
[0] => Array
(
[id] => 1533438473619168
)
[1] => Array
(
[id] => 77777777777777777
)
)
In the end, I'd like to have an array that looks like this: 最后,我想要一个看起来像这样的数组:
[0] => Array
(
[0] => Array
(
[id] => 1533438473619168
[count] => 3
)
[1] => Array
(
[id] => 3333333333333333
[count] => 1
)
[2] => Array
(
[id] => 5555555555555555
[count] => 1
)
[3] => Array
(
[id] => 77777777777777777
[count] => 1
)
)
Is there any general/easy way to do this without iterating through the first array for each value, comparing/storing the values in a temporary array, checking them, and adding to the count? 是否有任何常规/简便的方法,而无需遍历每个值的第一个数组,比较/存储临时数组中的值,检查它们并增加计数呢?
To get this exact format you may need to iterate thought your current array and do the counting manually, however php has the array_count_values() and array_unique() functions for this kind of thing: 为了获得这种精确格式,您可能需要迭代当前数组并手动进行计数,但是php具有针对这种情况的array_count_values()和array_unique()函数:
http://php.net/manual/en/function.array-count-values.php http://php.net/manual/zh/function.array-count-values.php
http://php.net/manual/en/function.array-unique.php http://php.net/manual/zh/function.array-unique.php
Because you are only concerned with the deepest values of the array, using array_walk_recursive
seems suitable for this. 因为您只关心数组的最深值,所以使用
array_walk_recursive
似乎很适合。 Note that a reference to the output array $counted
is used in the callback. 注意,在回调中使用了对输出数组
$counted
的引用。
array_walk_recursive($ids, function($id, $k) use (&$counted) {
$counted[$id] = isset($counted[$id]) ? $counted[$id] + 1 : 1;
});
Using the id as the key in the $counted
array will simplify the counting. 在
$counted
数组中使用id作为键将简化计数。 The result of this will be somewhat different from your suggested output, but in my opinion it would actually be simpler to use. 其结果将与您建议的输出有所不同,但我认为它实际上更易于使用。 (eg
foreach ($counted as $id => $count) {...
). (例如
foreach ($counted as $id => $count) {...
)。
$counted = array(
"1533438473619168" => 3
"3333333333333333" => 1
"5555555555555555" => 1
"77777777777777777" => 1);
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