[英]Select nth-last-child when not every element has the selecting class-jquery
I'm looking for something like the following CSS4 selector in jQuery
: :nth-last-match(selector)
我正在寻找类似jQuery
的以下CSS4选择器的东西:nth-last-match(selector)
I need to select the second to last element from a list of elements where not every element has a class
- Please see the following example highlighting what i am hopeing to achieve. 我需要从不是每个元素都有一个class
的元素列表中选择倒数第二个元素-请参阅以下示例,突出显示我希望实现的目标。
$('.select:nth-last-child(2)').addClass('selected');
.test.selected { color:red; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div> <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> <div class="test">a</div> <div class="test select">EXPECTED SELECTION</div> //This element should be selected <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> </div>
Many Thanks. 非常感谢。
You can use .get() method with negative argument value: 您可以使用带负参数值的.get()方法:
var expected = $('div .select').get(-2);
$(expected).css('background', 'red');
So, .get(-1)
is the last element of this collection, and .get(-2)
is second from the end. 因此, .get(-1)
是此集合的最后一个元素, .get(-2)
是末尾的第二个元素。
Check the below snippet 检查以下代码段
var expected = $('div .select').get(-2); $(expected).css('background', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div> <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> <div class="test">a</div> <div class="test select">EXPECTED SELECTION</div> <div class="test">a</div> <div class="test select">a</div> <div class="test">a</div> </div>
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