preg_match_all 只返回索引为 0 的第一个数组，而不返回索引为 1 的数组

Question

1 . I'm trying to match some IDs from a from with url and return all IDs.

The code is as follow.

The string is something like this

"gfdgfds.php?id=67f8d4fd6d4&gfddgfds.php?
id=67f8d4f6d4&gfddgfds.php?id=67f8d4f6d4&gfdsgfds.php?id=67f8d4f6fdd4&"

Pattern

$pattern = '/p?id=[0-9A-Za-z]*/';

CODE

preg_match_all($pattern,$input,$matches);   
    //var_dump(count($matches));
     if( count($matches) > 0 ) {
         var_dump($matches);
        //return $matches[1];
     } else {
        die('No matches found.');    
    }

But from the above when I do var_dump($matches) I get.

array (size=1)
  0 => 

And I was expecting to get

array (size=1)
      0 =>array()
      1 =>array() // So I can use this.  

What am I missing here, thanks.

2 . Also, I'd like the $pattern = "'/p?id=[0-9A-Za-z]*/'" to match "php?id=value", not just any id=value.

Answer 1

Instead of using regex you can use parse_url function but don't know exactly what is your expected output but instead of preg_match_all use preg_match with following regex

(.php\?id=(\w+))

So your code looks like as

preg_match("/(.php\?id=(\w+))/",$your_string,$matches);