运行多个 bash 命令，如果其中之一在 bash 中失败，则返回 false

Question

I am setting up a script that will execute a series of bundle exec rspec commands and I want it to return false if any of them fail. But I still want it to run all the tests. Is there a shorter way to accomplish this without a bunch of if or test statements?

Answer 1

I'm doing it currently like this, but I'll update the answer with nicer syntax if I'm able to write a bash function to handle this:

#!/bin/sh
set +x

RETVAL=0

command1 || RETVAL=1
command2 || RETVAL=1
command3 || RETVAL=1

exit $RETVAL

Answer 2

Track their exit code in a variable, and exit with it. I added the line number to for troubleshooting what broke.

declare -i r_code=0    # return code
command1 || { r_code+=$?; echo "ERROR at $LINENO
}

command2 || { r_code+=$?; echo "ERROR at $LINENO
}

exit $r_code

Answer 3

This is a for loop that will go through all the return codes and if one failed will exit with the first seen failed return code.

i=0
rc=0
command1 
rcode[i]=$?
i=i+1
command2
rcode[i]=$? ... n
for i in "${rcode}"
do
   if [ $i -ne 0 ]; then
      rc=$i
      break
   fi
done
exit $rc