如何使用php在登录页面上显示登录错误消息
[英]How to display login error message on the login page with php
问题描述
When login is successful, the user is redirected to the main page of my site.
登录成功后，用户将被重定向到我网站的主页。 My code redirects the user to a blank page when they input incorrect login details (login_parse.php), and here the error message 'Login unsuccessful' appears.当用户输入错误的登录详细信息 (login_parse.php) 时，我的代码将用户重定向到一个空白页面，并在此处显示错误消息“登录失败”。 I want the error message to appear on the login page (index.php).我希望错误消息出现在登录页面 (index.php) 上。
Login page:登录页面：
<?php session_start(); ?>
<!DOCTYPE html>
<html>
<link rel="stylesheet" type="text/css" href="style.css">
<head>
</head>
<body>
<form id='registration_form' action='registration.php' method='post'>
<input id ='new_username' type='text' name='new_username' placeholder='Create a username' oninvalid="this.setCustomValidity('Please create a username')"required></input>
<input id ='new_password' type='password' name='new_password' placeholder='Create a password' oninvalid="this.setCustomValidity('Please create a password')" required></input>
<input id ='new_email' type='email' name='new_email' placeholder='Enter a valid student.lboro.ac.uk email address'oninvalid="this.setCustomValidity('Please enter a valid student.lboro.ac.uk email address')" required></input>
<input id ='register_button' type='submit' value='Sign Up'/>
</form>
</body>
</html>
login_parse.php: login_parse.php:
<?php
session_start();
include "dbconnect.php";
if (isset($_POST['username'])) {
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * FROM Users WHERE username= '".$username."' AND password='".$password."' LIMIT 1";
$res = mysqli_query($db, $sql) or die(mysqli_error);
if (mysqli_num_rows($res) == 1) {
$row = mysqli_fetch_array($res);
$_SESSION['uid'] = $row['id'];
$_SESSION['username'] = $row['username'];
header("Location: shownewposts.php");
exit();
}
else {
echo "Login unsuccessful";
exit();
}
}
?>
1 个解决方案
解决方案1
1 2016-04-01 16:36:45
Look at http://www.phptherightway.com/#pdo_extension for input filter and PDO.查看http://www.phptherightway.com/#pdo_extension了解输入过滤器和 PDO。
You can create a session variable in else statement.您可以在 else 语句中创建会话变量。 Something Like:类似的东西：
<?php
session_start();
include "connect.php";
if (isset($_POST['username'])) {
unset( $_SESSION['errorMessage'] );
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * FROM Users WHERE username= '".$username."' AND password='".$password."' LIMIT 1";
$res = mysqli_query($db, $sql) or die(mysqli_error);
if (mysqli_num_rows($res) == 1) {
$row = mysqli_fetch_array($res);
$_SESSION['uid'] = $row['id'];
$_SESSION['username'] = $row['username'];
header("Location: shownewposts.php");
exit();
}
else {
$_SESSION['errorMessage'] = true;
header("Location: index.php");
exit();
}
}
?>
And in index.php check if session variabile exists and print message并在 index.php 检查会话变量是否存在并打印消息
<?php session_start(); ?>
<!DOCTYPE html>
<html>
<link rel="stylesheet" type="text/css" href="style.css">
<head>
</head>
<body>
<?php
if (isset($_SESSION['errorMessage'])){
echo "<span style='color:red;'>Check your input</span>";
}
?>
<form id='registration_form' action='registration.php' method='post'>
<input id ='new_username' type='text' name='new_username' placeholder='Create a username' oninvalid="this.setCustomValidity('Please create a username')"required></input>
<input id ='new_password' type='password' name='new_password' placeholder='Create a password' oninvalid="this.setCustomValidity('Please create a password')" required></input>
<input id ='new_email' type='email' name='new_email' placeholder='Enter a valid student.lboro.ac.uk email address'oninvalid="this.setCustomValidity('Please enter a valid student.lboro.ac.uk email address')" required></input>
<input id ='register_button' type='submit' value='Sign Up'/>
</form>
</body>
</html>
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