Bash：将目录路径不包含特定字符串的所有目录移动

Question

Let's say I have a directory with two subdirectories A and G. Directory A contains two subdirectories (B and C). Directory B also contains two subdirectories (D and E). Finally, directory D contains directory F.

.
├── A
│   ├── B
│   │   ├── D
│   │   │   └── F
│   │   └── E
│   └── C
└── G

Now, I want to move all directories where their path does not contain B/D to directory G. Assuming I'm in the top directory where A and G exist, I'm trying this command:

    $shopt -s extglob
    $mv !(*B/D*) ./G

But I'm getting this error: mv: rename !(*B/D*) to ./G/*: No such file or directory . Any ideas? I'm also open to other ways of solving the problem.

Answer 1

Using find :

find A/ -depth -type d -not \( -name *A* -o -name *B* -o -name *D* \) -exec mv -t G/ {} +

Example:

$ tree
.
├── A
│   ├── B
│   │   ├── D
│   │   │   └── F
│   │   └── E
│   └── C
└── G

$ find A/ -depth -type d -not \( -name *A* -o -name *B* -o -name *D* \) -exec mv -t G/ {} +

$ tree
.
├── A
│   └── B
│       └── D
└── G
    ├── C
    ├── E
    └── F

---

If your mv does not have -t option:

find A/ -depth -type d -not \( -name *A* -o -name *B* -o -name *D* \) -exec mv {} G/ \;

Answer 2

这是正确的答案：

find A/ -depth -type d -not \( -wholename "*B" \) -not \( -wholename "*B/D*" \) -exec sh -c 'mkdir -p G/`dirname "{}"`; mv "{}" G/`dirname "{}"`' \;