[英]python how to mock a method?
I want to test a http post method, this method will call some service, but the service cannot work in local test machine, so I want to mock it.我想测试一个http post方法,这个方法会调用一些服务,但是该服务不能在本地测试机上工作,所以我想模拟它。
test.py:测试.py:
@route(bp, '/count', methods=['POST'])
def count():
from module import service
...
total, ids = service(id, page, count) // total is a integer, ids is a list.
...
return {'total': total, 'ids': ids}
test case:测试用例:
@mock.patch("module.service")
def test_search_user(self, mock_service):
mock_service.return_value=(1, [])
url = url_for('users.count')
params = { .... }
response = self._test_app.post_json(
url, params, headers=self.request_headers, expect_errors=True)
self.assertEqual(response.status_code, 200)
but test case is always failed, it tried to call service
method, but it cannot work on my machine.但是测试用例总是失败,它试图调用
service
方法,但它不能在我的机器上工作。 I just want to mock it, but doesn't work.我只是想嘲笑它,但不起作用。
Anyone can help me!任何人都可以帮助我! Thanks in advance!
提前致谢!
According to @syntonym answer, my test case should be wrote like this:根据@syntonym 的回答,我的测试用例应该这样写:
@mock.patch("test.service")
def test_search_user(self, mock_service):
mock_service.return_value=(1, [])
@mock.patch
actually takes the lookup name - not the place where the object you want to patch acutally resides. @mock.patch
实际上采用查找名称 - 而不是您要修补的对象实际驻留的位置。 The documentation reads : 文档内容如下:
patch() works by (temporarily) changing the object that a name points to with another one.
patch() 通过(临时)将名称指向的对象更改为另一个对象。 [...] The basic principle is that you patch where an object is looked up, which is not necessarily the same place as where it is defined.
[...] 基本原则是在查找对象的位置打补丁,这不一定与定义它的位置相同。
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