如何在Groovy中将列表转换为字符串并删除括号而不使用替换？

Question

So I have the following code where I add some elements to a list, sort them and print as a string..

 def officeWorkers = []
 officeWorkers << "Jim Halpert"
 officeWorkers << "Dwight Shrute"
 officeWorkers << "Toby Flenderson"
 officeWorkers.sort()
 println("I wish my co workers were ${officeWorkers.toString()}")

The resulting string has opening and closing brackets ('[', ']') which I don't want ("I wish my co workers were [Dwight Shrute, Jim Halpert, Toby Flenderson]").

It seems one way to remove those brackets is to use String's replace function as suggested here .

But what if in the actual list I am using there are already brackets in the values, they would get replaced also.

So is there a way to print out this list as a string without having those brackets show up and without using the replace function?

Answer 1

使用加入：

println("I wish my co workers were ${officeWorkers.join(', ')}")