Python日志python解释器输出

Question

I tried to build a logger that also loggs the full output from the python interpreter, what you normally see on the console.

This is my suggestion, it did not work.

logger = logging.getLogger()
stdoutStreamHandler = logging.StreamHandler(sys.stdout)
stderrStreamHandler = logging.StreamHandler(sys.stderr)
fileHandler = logging.FileHandler(logpath)
logger.addHandler(stdoutStreamHandler)
logger.addHandler(stderrStreamHandler)

Answer 1

Unsure what you mean by logging the full output from the Python Interpreter, do you mean the command-line interpreter or the background interpreter at run-time?

Either way this may help: trace

This will allow you to execute any code with the trace, and will also allow you to write it out to a file:

 import sys import trace # create a Trace object, telling it what to ignore, and whether to # do tracing or line-counting or both. tracer = trace.Trace( ignoredirs=[sys.prefix, sys.exec_prefix], trace=0, count=1) # run the new command using the given tracer tracer.run('main()') # make a report, placing output in the current directory r = tracer.results() r.write_results(show_missing=True, coverdir=".") 

I have not yet used it myself, but it could be possible to execute

logger.debug(r)

Which would create a record in your log file of the debug log level, you could, of course, change that to info, warning, error or critical.