将字符串与正则表达式匹配将返回null

Question

I am trying to match a string for two cases by a single regular expressing in JavaScript. The string can be in any one of the given formats

//Singapore
//Singapore (country)

I have tried the following regular expression to match the strings

"singapore".match(/(.*) (?:\((.*)\))?/)
//null
"singapore (country)".match(/(.*) (?:\((.*)\))?/)
//["singapore (country)", "singapore", "country"]

I want both the results to return an array like the 2nd case where the 3rd entry in the array can be undefined/empty or not present at all but the result should not be null.

Can this be done by a single regular expression. If yes then what is the mistake in the above expression

Answer 1

您需要将空格放在可选组中，因为在仅"singapore"的情况下不是这样： /^([^\\(]*)(?: \\(([^\\)]*)\\))?$/