具有组python的多行正则表达式

Question

looking for some assistance from regex experts for my below requirement. I have a string of the format

if (x==True) then
    operation1
end
if (y==False) then
    operation2
    operation3
end
if (z==1) then
   operation4
end

I'm looking for this multiline string to be divided into groups as below.

('x==True', 'operation1')
('y==False', 'operation2', 'operation3')
('z==1', 'operation4')

Answer 1

Try this regex:

if\s+\(([^)]+)\)\s+then\s+([\s\S]+?)end

Description

Demo

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Answer 2

reg = r"if\s+\((.*?)\)\s+then\s(.*?)end"
match = re.findall(reg, text, re.DOTALL)

Answer 3

A funny way with the parse module:

import re
from parse import *

s='''if (x==True) then
    operation1
end
if (y==False) then
    operation2
    operation3
end
if (z==1) then
   operation4
end'''

for block in re.split(r'(?<=\nend)\n', s):
    m = parse("if ({}) then\n{}\nend", block)
    print(tuple([m[0]]+m[1].strip().split()))