XML 反序列化不适用于抽象类
[英]XML Deserialization doesn't work with abstract class
问题描述
I'm trying to deserialize from a xml string to an object.
我正在尝试将 xml 字符串反序列化为对象。 But my obect is always null.但我的对象始终为空。
I have an abstract class (Response), a class that inherits from "Response" (DirectorSearchResponse), and an object in the class "DirectorSearchResponse" (HeaderResponse).我有一个抽象类（Response），一个继承自“Response”（DirectorSearchResponse）的类，以及“DirectorSearchResponse”（HeaderResponse）类中的一个对象。 This object is always null after deserialization.反序列化后，此对象始终为空。
Response.cs响应文件
public abstract class Response
{
public HeaderResponse Header { get; set; }
public Response()
{
}
}
DirectorSearchResponse.cs DirectorSearchResponse.cs
[XmlRoot("xmlresponse")]
public class DirectorSearchResponse : Response
{
public DirectorSearchResponse() : base()
{
/* DO NOTHING */
}
}
HeaderResponse.cs HeaderResponse.cs
[XmlRoot("header")]
public class HeaderResponse
{
[XmlElement("toto")]
public String toto { get; set; }
public HeaderResponse()
{
}
}
My running code :我的运行代码：
/* DESERIALIZE */
String toto = "<xmlresponse><header><toto>tutu</toto><reportinformation><time>08/04/2016 13:33:37</time><reporttype> Error</reporttype><country>FR</country><version>1.0</version><provider>www.creditsafe.fr</provider><chargereference></chargereference></reportinformation></header><body><errors><errordetail><code>110</code><desc></desc></errordetail></errors></body></xmlresponse>";
XmlSerializer xsOut = new XmlSerializer(typeof(DirectorSearchResponse));
using (TextReader srr = new StringReader(toto))
{
DirectorSearchResponse titi = (DirectorSearchResponse)xsOut.Deserialize(srr);
}
When I execute my code, the object "titi" is instanciate, but "Header" is always null.当我执行我的代码时，对象“titi”是实例化的，但“Header”始终为空。
How retrieve the "toto" value from xml ?如何从 xml 检索“toto”值？
2 个解决方案
解决方案1
1 已采纳 2016-04-08 17:12:45
XML is case sensitive, so you need to use [XmlElement("header")] to inform the serializer of the correct element name for the Header property: XML 区分大小写，因此您需要使用[XmlElement("header")]通知序列化程序Header属性的正确元素名称：
public abstract class Response
{
[XmlElement("header")]
public HeaderResponse Header { get; set; }
public Response()
{
}
}
The [XmlRoot("header")] you have applied to HeaderResponse only controls its element name when it is the root element of an XML document.您已应用于HeaderResponse的[XmlRoot("header")]仅在它是 XML 文档的根元素时控制其元素名称。
解决方案2
0 2016-04-08 15:53:29
You need to add the link to the abstract class like this :您需要像这样将链接添加到抽象类：
[XmlRoot(ElementName = "Response")]
public abstract class Response
{
public HeaderResponse Header { get; set; }
public Response()
{
}
}
[XmlRoot(ElementName = "Response")]
public class DirectorSearchResponse : Response
{
public DirectorSearchResponse() : base()
{
/* DO NOTHING */
}
}
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