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无法显示PDO查询的结果

[英]Cannot display results from query with PDO

I am trying to get the results from a query which should get multiple results and display them all on the page. 我试图从查询中获取结果,该查询应获取多个结果并将其全部显示在页面上。 However it is not displaying any of the content. 但是,它不显示任何内容。 My guess is a mistake in my syntax for me loop. 我的猜测是我的循环语法错误。 But I am unsure. 但是我不确定。

//query to find comments about this map
$query = "
        SELECT 
           user_id,
           comment
         FROM map_comments
         WHERE
           map_id = :mapID
         ";  

//query parameters
$query_params = array(
  ':mapID' => $_SESSION['mapID']
);

try
{
    //execute query
    $statement = $db->prepare($query);
    $result = $statement->execute($query_params);
    //get all results
    $comments = $result->fetchAll;
    if($result === FALSE) 
    { 
      die(mysql_error()); // TODO: better error handling
    }
}
catch(PDOException $e)
{
    die("failed to find comments");
}

foreach($comments as &$comment)
      { 
        echo $comment;
      }

You need parentheses after a function to call it. 您需要在函数后加上括号才能调用它。

$comments = $result->fetchAll;

should be: 应该:

$comments = $statement->fetchAll();

Also, the check for if ($result == FALSE) should be before this line. 另外,检查if ($result == FALSE)是否应此行之前 And you can't use mysql_error() if you're using PDO, you should use $statement->errorInfo() . 如果使用PDO,则不能使用mysql_error() ,而应使用$statement->errorInfo() Or you should enable PDO::ERRMODE_EXCEPTION on the connection, and the catch block will be invoked. 或者,您应该在连接上启用PDO::ERRMODE_EXCEPTION ,然后catch块将被调用。 You should then use $db->errorInfo() in the error message that it prints. 然后,您应该在打印的错误消息中使用$db->errorInfo()

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