简体   繁体   English

const类型的容器的const_iterator类型

[英]const_iterator type of a container of const types

If I compile the code below: 如果我编译下面的代码:

#include <list>

using iter_t = std::list<const unsigned>::const_iterator;

int main(int, char**) {
  return 0;
}

I get the following compile error: 我收到以下编译错误:

In file included from /usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/x86_64-apple-darwin13.4.0/bits/c++allocator.h:33:0,
             from /usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/bits/allocator.h:46,
             from /usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/list:61,
             from main.cpp:1:
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/ext/new_allocator.h: In instantiation of 'class __gnu_cxx::new_allocator<const unsigned int>':
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/bits/allocator.h:92:11:   required from 'class std::allocator<const unsigned int>'
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/bits/stl_list.h:315:9:   required from 'class std::_List_base<const unsigned int, std::allocator<const unsigned int> >'
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/bits/stl_list.h:447:11:   required from 'class std::list<const unsigned int>'
main.cpp:3:41:   required from here
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/ext/new_allocator.h:93:7: error: 'const _Tp* __gnu_cxx::new_allocator<_Tp>::address(__gnu_cxx::new_allocator<_Tp>::const_reference) const [with _Tp = const unsigned int; __gnu_cxx::new_allocator<_Tp>::const_pointer = const unsigned int*; __gnu_cxx::new_allocator<_Tp>::const_reference = const unsigned int&]' cannot be overloaded
   address(const_reference __x) const _GLIBCXX_NOEXCEPT
   ^
/usr/local/Cellar/gcc/4.9.2_1/include/c++/4.9.2/ext/new_allocator.h:89:7: error: with '_Tp* __gnu_cxx::new_allocator<_Tp>::address(__gnu_cxx::new_allocator<_Tp>::reference) const [with _Tp = const unsigned int; __gnu_cxx::new_allocator<_Tp>::pointer = const unsigned int*; __gnu_cxx::new_allocator<_Tp>::reference = const unsigned int&]'
   address(reference __x) const _GLIBCXX_NOEXCEPT
   ^

I get roughly the same error message if I change the container type from std::list to std::vector , std::deque or std::forward_list . 如果将容器类型从std::list更改为std::vectorstd::dequestd::forward_list ,我会得到大致相同的错误消息。 If I change the template argument from const unsigned to unsigned it compiles fine. 如果我将模板参数从const unsigned更改为unsigned则可以正常编译。

What's going on here? 这里发生了什么? I can't see why it wouldn't compile. 我不明白为什么它不能编译。

Visual C++ 2015 gives the clarifying diagnostic Visual C ++ 2015提供了明确的诊断

The C++ Standard forbids containers of const elements because allocator<const T> is ill-formed. C ++标准禁止使用const元素容器,因为allocator<const T>格式不正确。

As I understand it, this is because an allocator's allocate method returns a pointer to an array of uninitialized T items, and if T is const then these items can never be initialized. 据我了解,这是因为分配器的allocate方法返回了指向未初始化的T项目数组的指针,并且如果Tconst则这些项目将永远无法初始化。

I can't find any explicit statement that allocator<const T> is ill-formed, so it is presumably a consequence of the semantics. 我找不到任何明确声明allocator<const T>格式不正确,因此大概是语义的结果。

As Dieter Lücking notes in a comment , there is a direct clash for const type T between the two member functions that provide address of a reference and const_reference , because these are equal when the type is const . 正如DieterLücking 在评论中指出的那样 ,在提供reference地址和const_reference的两个成员函数之间, const类型T存在直接冲突,因为当类型为const时,它们相等。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM