[英]QFlags and QVariant
What I am trying to do is to simply store a QFlags
in a QVariant
. 我想要做的是简单地将
QFlags
存储在QVariant
。
The Flags definition: 旗帜定义:
class EnumObject : public QObject
{
Q_OBJECT
public:
enum DemoFlag {
SomeFlag0 = 0x00,
SomeFlag1 = 0x01,
SomeFlag2 = 0x02
};
Q_DECLARE_FLAGS(DemoFlags, DemoFlag)
Q_FLAG(DemoFlags)
};
Now all I do is to construct a qvariant using the QVariant::fromValue
function: 现在我所做的就是使用
QVariant::fromValue
函数构造一个qvariant:
QVariant var = QVariant::fromValue<EnumObject::DemoFlags>(EnumObject::SomeFlag2);
qDebug() << var;
The debug output shows: 调试输出显示:
QVariant(EnumObject::DemoFlags, )
So, for whatever reason QVariant seems to be unable to store the flags? 那么,无论出于何种原因,QVariant似乎都无法存放旗帜? It does recognize the type, but seems unable to store the value.
它确实识别出类型,但似乎无法存储该值。 Did I miss something?
我错过了什么? If I register an enum instead, everything works fine.
如果我注册枚举,一切正常。
Note: I do know that I can store the value by casting it to an interger and back, but this is not possible for me, because the QVariant creation is part of a generic method. 注意:我确实知道我可以通过将值转换为整数和后面来存储该值,但这对我来说是不可能的,因为QVariant创建是泛型方法的一部分。
Actually it saves. 实际上它节省了。 But value is not showed for qDebug().
但是qDebug()没有显示值。 It can be seen if value is extracted from QVariant:
可以看出是否从QVariant中提取了值:
EnumObject::DemoFlags val = var.value<EnumObject::DemoFlags>();
qDebug() << val;
Gives: 得到:
QFlags<EnumObject::DemoFlags>(SomeFlag2)
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