SQLite3将单个占位符值传递给python中的函数-Newbie

Question

I am new in SQLite and I need help in this one. I am trying to make a simple function in python that takes a database name and table name and make it display the whole table. I wrote it like this:

def columnlist(dbname,tablename):
dbname=str(dbname)
tablename=str(tablename)
conn = sqlite3.connect(dbname) #connection
c = conn.cursor()
c.execute('SELECT sql FROM sqlite_master WHERE type=\'table\' AND name=?',tablename) #list columns in table 'students'
pp.pprint(c.fetchall())
conn.close()

Somehow, when I try to run it, it gave me the following error:

File "C:/Users/XXXX/Documents/Python Scripts/Assignment 3/L6Q1.py", line 20, in columnlist c.execute('SELECT sql FROM sqlite_master WHERE type=\\'table\\' AND name=(?)',str(tablename)) #list columns in table 'students'

ProgrammingError: Incorrect number of bindings supplied. The current statement uses 1, and there are 8 supplied.

Can anyone please show me what I did wrong? Thanks

Answer 1

The problem is that you need to pass in a tuple instead of a single value. What you would want to do is change the line into the following:

c.execute('SELECT sql FROM sqlite_master WHERE type=\'table\' AND name=(?)',(tablename,))

Hope this helps :)